let a = 1 * 3 == 4;
let b = 3/4 == *a;
let c = (a->b.c->d) / 2;
let d = 2 / a->b.c->d;
let e = a->b.c->d / 2;
let f = a.b.c.d / 2;
let g = a.b[*a.c] * 5;